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-n^2+10n+24=0
We add all the numbers together, and all the variables
-1n^2+10n+24=0
a = -1; b = 10; c = +24;
Δ = b2-4ac
Δ = 102-4·(-1)·24
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-14}{2*-1}=\frac{-24}{-2} =+12 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+14}{2*-1}=\frac{4}{-2} =-2 $
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